A voltmeter is constructed from a 25 coil connected in series with...

The total resistance of the voltmeter is the sum of the resistance of the coil and the series resistor.

$R = R_c + R_s$

Substituting the given values:

$R = 25 \Omega + 575 \Omega = 600 \Omega$

The maximum potential difference $V$ that the voltmeter can measure corresponds to the full scale deflection current $I_g$.

$V = I_g R$

Given $I_g = 10 \text{ mA} = 10 \times 10^{-3} \text{ A}$, we get:

$V = (10 \times 10^{-3} \text{ A}) \times (600 \Omega)$

$V = 6 \text{ V}$