A conducting circular loop with a radius of 5.0 cm is placed perpendicular to a magnetic field of 0.50 T . It is then removed from the field over a period of 0.50 s . Determine the average emf generated in the loop during this interval.

Step-by-step solution

The initial magnetic flux linked with the loop is given by: _ i = B A = B r² Substituting the given values: _ i = 0.50 (0.05)² = 0.00125 Wb When the loop is removed from the magnetic field, the final magnetic flux becomes: _ f = 0 The magnitude of the average induced emf is: e = | t | = _ i - _ f t e = 0.00125 - 0 0.50 = 0.0025 V e = 0.0025 3.14 0.00785 V 0.0078 V