A square-shaped copper coil has edges of length 50 cm and comprises 50 turns. It is positioned perpendicular to a 1.0 T magnetic field. The coil is removed from the magnetic field in 0.25 s . Determine the magnitude of the average emf induced in the loop during its removal.

Step-by-step solution

Given: Number of turns, N = 50 Edge length, l = 50 cm = 0.5 m Area of the coil, A = l^2 = (0.5)^2 = 0.25 m ^2 Initial magnetic field, B = 1.0 T Time interval, t = 0.25 s The initial magnetic flux through a single turn is: _i = BA = 1.0 0.25 = 0.25 Wb Since the coil is removed from the magnetic field, the final magnetic flux is: _f = 0 The magnitude of the average induced emf is given by Faraday's law of induction: |e| = N | t | = N | _f - _i t | Substituting the values: |e| = 50 | 0 - 0.25 0.25 | = 50 1 = 50 V