A square-shaped copper coil with edges of length 50 cm contains 50 turns. It is placed perpendicular to a 1.0 T magnetic field. The coil is removed from the magnetic field in 0.25 s and restored to its original place in the subsequent 0.25 s . The resistance of the coil is 25 . Assuming the coil moves with uniform velocity during its removal and restoration, determine the thermal energy developed in the coil during i

Step-by-step solution

Area of the square coil, A = a^2 = (0.5)^2 = 0.25 m ^2 Initial magnetic flux linked with the coil, _i = NBA = 50 1.0 0.25 = 12.5 Wb Final magnetic flux linked with the coil after removal, _f = 0 Since the coil moves with uniform velocity, the rate of change of flux is constant. The induced EMF is: E = | t | = 12.5 - 0 0.25 = 50 V Thermal energy developed during the removal is: H = E^2 R t = (50)^2 25 0.25 = 2500 25 0.25 = 100 0.25 = 25 J