As depicted in the figure, a square loop of side 5 ext cm is moved towards the right at a constant speed of 1 ext cm/s . The front edge enters the 20 ext cm wide magnetic field at t = 0 . Determine the emf induced in the loop at t = 2 ext s .

Step-by-step solution

Given: Magnetic field, B = 0.6 T Side of the square loop, l = 5 cm = 0.05 m Velocity of the loop, v = 1 cm/s = 0.01 m/s Distance travelled by the front edge of the loop in t = 2 s is: x = vt = 1 cm/s 2 s = 2 cm Since 2 cm is less than the side length of the loop ( 5 cm ), the loop is partially inside the magnetic field and is still entering it. The magnetic flux through the loop is changing. The induced emf is given by the motional emf formula: = Blv Substituting the values: = 0.6 0.05 0.01 = 3 10⁻⁴ V