A square loop of side 5 ext cm travels towards the right at a constant speed of 1 ext cm/s . The front edge of the loop enters a 20 ext cm wide uniform magnetic field of 0.6 ext T perpendicular to the plane of the loop at t = 0 . Determine the emf induced in the loop at t = 10 ext s .

Step-by-step solution

Given: Side of the square loop, a = 5 cm Speed of the loop, v = 1 cm/s Width of the magnetic field, w = 20 cm Time, t = 10 s Distance travelled by the front edge of the loop in 10 s is: d_ front = v t = 1 cm/s 10 s = 10 cm The position of the rear edge of the loop at this time is: d_ rear = d_ front - a = 10 cm - 5 cm = 5 cm Since the magnetic field extends from 0 to 20 cm , and both the front edge ( 10 cm ) and the rear edge ( 5 cm ) are within this region, the entire square loop is completely inside the uniform m