A square loop of side 5 ext cm is travelling towards the right at a constant speed of 1 ext cm/s . The front edge of the loop enters a 20 ext cm wide uniform magnetic field of 0.6 ext T perpendicular to the plane of the loop at t = 0 . Compute the emf induced in the loop at t = 22 ext s .

Step-by-step solution

Given, side of the square loop, a = 5 cm = 0.05 m Speed of the loop, v = 1 cm/s = 0.01 m/s Magnetic field, B = 0.6 T Width of the magnetic field, w = 20 cm Distance travelled by the front edge of the loop in t = 22 s is: d = v t = 1 22 = 22 cm The magnetic field exists from x = 0 to x = 20 cm . At t = 22 s , the front edge is at x = 22 cm (outside the magnetic field) and the rear edge is at x = 22 - 5 = 17 cm (inside the magnetic field). Since the loop is partially outside and exiting the magnetic field, the magnet