A square loop of side 5 ext cm is moving towards the right at a uniform speed of 1 ext cm/s . At t = 0 , its front edge enters a 20 ext cm wide uniform magnetic field of magnitude 0.6 ext T perpendicular to the plane of the loop. Calculate the emf induced in the loop at t = 30 ext s .

Step-by-step solution

Given: Side of the square loop, a = 5 cm Speed of the loop, v = 1 cm/s Width of the magnetic field, d = 20 cm At t = 0 , the front edge of the loop enters the magnetic field at x = 0 . Distance traveled by the front edge in t = 30 s is: x_ front = v t = 1 cm/s 30 s = 30 cm The position of the rear edge of the loop at t = 30 s is: x_ rear = x_ front - a = 30 cm - 5 cm = 25 cm The magnetic field exists only in the region from x = 0 to x = 20 cm . Since the rear edge of the loop is at 25 cm , which is beyond the magne