As shown in the figure, a square loop of side 5 cm travels towards the right with a constant speed of 1 cm/s . At t = 0 , its front edge enters a magnetic field of width 20 cm . Determine the total heat produced in the loop over the time interval from 0 to 30 s , given that the loop's resistance is 4.5 m .

Step-by-step solution

The heat is produced in the loop only when the magnetic flux through it changes, which occurs when the loop is entering and exiting the magnetic field. Given parameters: Side of the square loop, a = 5 cm = 0.05 m Velocity of the loop, v = 1 cm/s = 0.01 m/s Magnetic field, B = 0.6 T Resistance of the loop, R = 4.5 m = 4.5 10⁻³ Width of the magnetic field, w = 20 cm = 0.2 m The induced emf E when the loop is entering or exiting the field is given by: E = Bav E = 0.6 0.05 0.01 = 3 10⁻⁴ V The power dissipated as heat d