Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
Concepts Of Physics MCQ Edition [Volume 2]PhysicsElectromagnetic Induction

Comprising 1000 turns, a coil with a radius of 10 cm and a resistance of 40 is positioned such that its plane is vertical and its axis aligns parallel to the magnetic meridian. This coil is connected to a galvanometer and subsequently rotated by an angle of 180^ about its vertical diameter. Determine the charge that flows through the galvanometer, given that the horizontal component of the earth's magnetic field is B

Options

  1. A3.0 10⁻⁵ C
  2. B0.75 10⁻⁵ C
  3. C1.5 10⁻⁵ C
  4. D6.0 10⁻⁵ C

Correct answer

C. 1.5 10⁻⁵ C

Step-by-step solution

Initial magnetic flux linked with the coil is _i = NBA (0^ ) = NBA Final magnetic flux linked with the coil after 180^ rotation is _f = NBA (180^ ) = -NBA Magnitude of change in magnetic flux is | | = | _f - _i| = 2NBA The charge flowing through the circuit is given by q = | | R = 2NBA R Substituting the given values: N = 1000 B = 3.0 10⁻⁵ T A = r^2 = (0.1)^2 = 0.01 m ^2 R = 40 q = 2 1000 3.0 10⁻⁵ 0.01 40 q = 60 10⁻⁵ 40 = 1.5 10⁻⁵ C

Practice Electromagnetic Induction on Quantrex Academy →

More from Electromagnetic Induction

List-I contains four conducting loops lying in the XY plane, as shown in the figures. The loops are rotating about Z axis passing through the point O with time period T in clockwis 2026A 30 cm long solenoid has 10 turns per cm and area of 5 cm ^2 . The current through the solenoid coil varies from 2 A to 4 A in 3.14 s. The e.m.f. induced in the coil is 10⁻⁵ V. Th 2026A square loop of side 2 cm is placed in a time varying magnetic field with magnitude as B = 0.4 (300t) Tesla. The normal to the plane of loop makes an angle of 60° with the field. 2026An inductor of inductance 10 mH having resistance of 100 , is connected to battery of E.M.F. 1.0 V through a switch as shown in the figure below. After switch is closed, the ratio 2026A metal rod of length L rotates about one end at origin with a uniform angular velocity . The magnetic field radially falls off as B(r) = B₀ e^ - r ; being a positive constant. The 2026A circular loop of radius 20 cm and resistance 2 is placed in a time varying magnetic field B = (2t^2 + 2t + 3) T . At t = 0 , for the plane of the loop being perpendicular to the 2026In the given circuit below inductance values of L₁ , L₂ and L₃ are same. The magnetic energy stored in the entire circuit is (U_t) and that stored in the L₂ inductor is (U_l) . U_t 2026A circular current loop of radius R is placed inside square loop of side length L(L >> R) such that they are co-planar and their centers coincide. The permeability of free space is 2026 Full Electromagnetic Induction list All Concepts Of Physics MCQ Edition [Volume 2] PYQs