Concepts Of Physics MCQ Edition [Volume 2]PhysicsElectromagnetic Induction
A conducting rod of length 20 cm undergoes pure translation at a uniform velocity of 10 cm s ⁻¹ perpendicular to its length. A uniform magnetic field of 0.10 T is present, directed perpendicular to the plane of motion. Determine the motional emf induced between the ends of the rod.
Options
- A4.0 10⁻³ V
- B2.0 10⁻² V
- C1.0 10⁻³ V
- D2.0 10⁻³ V
Correct answer
D. 2.0 10⁻³ V
Step-by-step solution
Given: Length of the rod, l = 20 cm = 0.2 m Velocity of the rod, v = 10 cm s ⁻¹ = 0.1 m s ⁻¹ Magnetic field, B = 0.10 T Since the velocity, length, and magnetic field are mutually perpendicular, the motional emf induced across the ends of the rod is given by: = Bvl Substituting the given values: = 0.10 0.1 0.2 = 0.002 V = 2.0 10⁻³ V