A metallic metre stick travels with a velocity of 2 m s ⁻¹ in a direction that is perpendicular to both its length and a uniform magnetic field of magnitude 0.2 T . Determine the emf induced between the ends of the stick.

Step-by-step solution

The length of the metallic metre stick is l = 1 m . The velocity of the stick is v = 2 m s ⁻¹ . The uniform magnetic field is B = 0.2 T . Since the stick moves in a direction perpendicular to both its length and the magnetic field, the induced motional emf is given by: = Bvl Substituting the given values: = 0.2 2 1 = 0.4 V