A right-angled triangle abc , formed from a metallic wire, travels at a uniform speed v in its plane. A uniform magnetic field B is present in the perpendicular direction. Determine the induced emf in the segment ab .

Step-by-step solution

The magnetic flux linked with the closed loop is given by = B A . Since the magnetic field B is uniform and the loop moves with a constant velocity v in a plane perpendicular to the magnetic field, the area A of the loop and the magnetic field B remain constant over time. Thus, the magnetic flux through the closed loop is constant. According to Faraday's law of electromagnetic induction, the induced emf in the loop is = - d dt . Since the flux is constant, d dt = 0 . Therefore, the induced emf in the closed loop ab