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Concepts Of Physics MCQ Edition [Volume 2]PhysicsElectromagnetic Induction

When an electric current of 4 A flows in a 200 -turn coil, a magnetic flux of 8 10⁻⁴ weber is linked with each turn. Determine the self-inductance of the coil.

Options

  1. A0.64 H
  2. B2 10⁻⁴ H
  3. C0.04 H
  4. D0.16 H

Correct answer

C. 0.04 H

Step-by-step solution

The total magnetic flux linked with the coil is given by N = L I , where N is the number of turns, is the flux linked with each turn, L is the self-inductance, and I is the current. Given: N = 200 I = 4 A = 8 10⁻⁴ Wb Substituting the values into the formula: L = N I L = 200 8 10⁻⁴ 4 L = 1600 10⁻⁴ 4 L = 400 10⁻⁴ H L = 0.04 H

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