Concepts Of Physics MCQ Edition [Volume 2]PhysicsElectromagnetic Induction
An LR circuit has a time constant of 40 ms . The circuit is connected at t = 0 and the steady-state current is found to be 2.0 A . Determine the current at t = 20 ms .
Options
- A1.73 A
- B1.21 A
- C0.79 A
- D0.39 A
Correct answer
C. 0.79 A
Step-by-step solution
The growth of current in an LR circuit is given by the equation: I(t) = I₀ (1 - e^ -t/ ) Given: Time constant, = 40 ms Steady-state current, I₀ = 2.0 A Time, t = 20 ms Substituting the values into the equation: I = 2.0 (1 - e^ -20/40 ) I = 2.0 (1 - e^ -0.5 ) Using the value e^ -0.5 0.6065 : I = 2.0 (1 - 0.6065) I = 2.0 0.3935 I = 0.787 A 0.79 A