An LR circuit includes an inductor of 500 mH , a resistor of 25.0 , and a 5.00 V emf connected in series. Determine the potential difference across the resistor at t = 20.0 ms .

Step-by-step solution

The time constant of the LR circuit is given by = L R . Substituting the given values: = 500 10⁻³ 25.0 = 0.02 s = 20.0 ms The current in the circuit at time t is given by: I = E R (1 - e^ -t/ ) The potential difference across the resistor is: V_R = IR = E (1 - e^ -t/ ) At t = 20.0 ms , we have t = . V_R = 5.00 (1 - e⁻¹ ) V_R = 5.00 (1 - 1 2.718 ) V_R 5.00 (1 - 0.368) = 5.00 0.632 = 3.16 V