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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Gauss's Law

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Gauss's Law

A charge Q is located at the centre of an initially uncharged,...

A charge QQ is located at the centre of an initially uncharged, hollow metallic sphere of radius aa. Determine the surface charge density on the inner surface and on the outer surface. If a charge qq is subsequently placed on the sphere, what will be the surface charge densities on the inner and outer surfaces? Also, find the electric field inside the sphere at a distance xx from the centre in both situations.

Options

  1. AInitial inner and outer densities: −Q4πa2-\dfrac{Q}{4\pi a^2}, Q4πa2\dfrac{Q}{4\pi a^2}
    Final inner and outer densities: −Q4πa2-\dfrac{Q}{4\pi a^2}, Q+q4πa2\dfrac{Q+q}{4\pi a^2}
    Electric field: Q4πε0x2\dfrac{Q}{4\pi\varepsilon_0 x^2}
  2. BInitial inner and outer densities: 00, Q4πa2\dfrac{Q}{4\pi a^2}
    Final inner and outer densities: −Q4πa2-\dfrac{Q}{4\pi a^2}, q4πa2\dfrac{q}{4\pi a^2}
    Electric field: Q+q4πε0x2\dfrac{Q+q}{4\pi\varepsilon_0 x^2}
  3. CInitial inner and outer densities: Q4πa2\dfrac{Q}{4\pi a^2}, −Q4πa2-\dfrac{Q}{4\pi a^2}
    Final inner and outer densities: Q4πa2\dfrac{Q}{4\pi a^2}, q−Q4πa2\dfrac{q-Q}{4\pi a^2}
    Electric field: Q4πε0x2\dfrac{Q}{4\pi\varepsilon_0 x^2}
  4. DInitial inner and outer densities: −Q4πa2-\dfrac{Q}{4\pi a^2}, Q4πa2\dfrac{Q}{4\pi a^2}
    Final inner and outer densities: 00, Q+q4πa2\dfrac{Q+q}{4\pi a^2}
    Electric field: 00

Correct answer

A. Initial inner and outer densities: −Q4πa2-\dfrac{Q}{4\pi a^2}, Q4πa2\dfrac{Q}{4\pi a^2}
Final inner and outer densities: −Q4πa2-\dfrac{Q}{4\pi a^2}, Q+q4πa2\dfrac{Q+q}{4\pi a^2}
Electric field: Q4πε0x2\dfrac{Q}{4\pi\varepsilon_0 x^2}

Step-by-step solution

When a charge QQ is placed at the centre of the uncharged hollow metallic sphere, the electric field inside the conducting material must be zero.

By Gauss's law, a charge −Q-Q is induced on the inner surface of the sphere. Since the sphere is initially uncharged, a charge +Q+Q appears on the outer surface.

Assuming the sphere is a thin shell of radius aa, the surface charge density on the inner surface is −Q4πa2-\dfrac{Q}{4\pi a^2} and on the outer surface is Q4πa2\dfrac{Q}{4\pi a^2}.

When an additional charge qq is given to the sphere, it resides entirely on the outer surface. The charge on the inner surface remains −Q-Q to maintain zero electric field inside the metal.

The total charge on the outer surface becomes Q+qQ + q.

The new surface charge densities are −Q4πa2-\dfrac{Q}{4\pi a^2} on the inner surface and Q+q4πa2\dfrac{Q+q}{4\pi a^2} on the outer surface.

For a point at a distance xx from the centre inside the cavity (x<ax < a), a spherical Gaussian surface encloses only the central charge QQ. The uniform charge distributions on the spherical shell do not contribute to the electric field inside the cavity.

Applying Gauss's law, E(4πx2)=Qε0E (4\pi x^2) = \dfrac{Q}{\varepsilon_0}, which gives E=Q4πε0x2E = \dfrac{Q}{4\pi\varepsilon_0 x^2}. This electric field remains the same in both situations.
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