Two large conducting plates are positioned parallel to each other and carry equal and opposite charges with surface density . Calculate the electric field to the right of the plates.

Step-by-step solution

Let the surface charge density of the positive plate be + and the negative plate be - . The electric field produced by a single large charged plate with surface charge density at any point outside it is given by E = 2 ₀ . For a point to the right of both plates: The electric field due to the positively charged plate (left plate) is directed away from it, i.e., towards the right, with magnitude E_+ = 2 ₀ . The electric field due to the negatively charged plate (right plate) is directed towards it, i.e., towards the