The steam point and the ice point of a mercury thermometer are marked as 80^ ^ ^ and 20^ ^ ^ , respectively. What will be the temperature on the centigrade scale when this thermometer reads 32^ ^ ^ ?

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Quantrex Academy · Accepted Answer

Correct answer: A. 20^ ^ ^ C

Using the principle of thermometry, the ratio of the difference in temperature readings to the fundamental interval is constant for any scale.

\dfrac{T - T_{\text{ice}}}{T_{\text{steam}} - T_{\text{ice}}} = \dfrac{C - 0}{100 - 0}

Given

T_{\text{ice}} = 20^{{}^{{}^{\circ}}}

,

T_{\text{steam}} = 80^{{}^{{}^{\circ}}}

, and

T = 32^{{}^{{}^{\circ}}}

.

Substituting the values:

\dfrac{32 - 20}{80 - 20} = \dfrac{C}{100}

\dfrac{12}{60} = \dfrac{C}{100}

\dfrac{1}{5} = \dfrac{C}{100}

C = 20^{{}^{{}^{\circ}}}\text{C}

The steam point and the ice point of a mercury thermometer are...

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