A platinum resistance thermometer registers 0^ ^ ^ at a resistance of 80 and 100^ ^ ^ at a resistance of 90 . Determine the temperature on the platinum scale when the resistance reaches 86 .

Correct answer: C. 60^ ^ ^ The temperature t on the platinum scale is given by the formula: t = R_t - R_0 R_ 100 - R_0 × 100^ ^ ^ Given: R_0 = 80 R_ 100 = 90 R_t = 86 Substituting the values into the formula: t = (86 - 80)/(90 - 80) × 100^ ^ ^ t = (6)/(10) × 100^ ^ ^ t = 60^ ^ ^

Concepts Of Physics MCQ Edition [Volume 2]

Exam: Concepts Of Physics MCQ Edition [Volume 2]
Subject: Physics
Chapter: Heat and Temperature

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Heat and Temperature

A platinum resistance thermometer registers 0^ ^ ^ at a resistance...

A platinum resistance thermometer registers

0^{}^{{}^{\circ}}

at a resistance of

80 \Omega

and

100^{}^{{}^{\circ}}

at a resistance of

90 \Omega

. Determine the temperature on the platinum scale when the resistance reaches

86 \Omega

Options

A $75^{}^{{}^{\circ}}$
B $86^{}^{{}^{\circ}}$
C $60^{}^{{}^{\circ}}$
D $40^{}^{{}^{\circ}}$

Correct answer

C. $60^{}^{{}^{\circ}}$

Step-by-step solution

The temperature

t

on the platinum scale is given by the formula:

t = \dfrac{R_t - R_0}{R_{100} - R_0} \times 100^{{}^{{}^{\circ}}}

Given:

R_0 = 80 \Omega

R_{100} = 90 \Omega

R_t = 86 \Omega

Substituting the values into the formula:

t = \dfrac{86 - 80}{90 - 80} \times 100^{{}^{{}^{\circ}}}

t = \dfrac{6}{10} \times 100^{{}^{{}^{\circ}}}

t = 60^{{}^{{}^{\circ}}}

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