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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Laws of Thermodynamics

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Laws of Thermodynamics

Water at 15^ ^ ^ C is contained inside a closed, thermally...

Water at 15^{}^{{}^{\circ}} C is contained inside a closed, thermally insulated copper vessel. The temperature increases to 17^{}^{{}^{\circ}} C after the vessel is vigorously shaken for 1515 minutes. The mass of the water is 200 g200 \text{ g} and the mass of the vessel is 100 g100 \text{ g}. The specific heat capacities of copper and water are 420 J kg−1 K−1420 \text{ J kg}^{-1} \text{ K}^{-1} and 4200 J kg−1 K−14200 \text{ J kg}^{-1} \text{ K}^{-1}, respectively. Ignore any thermal expansion. Calculate the work that has been done on this system.

Options

  1. A1680 J1680 \text{ J}
  2. B3528 J3528 \text{ J}
  3. C84 J84 \text{ J}
  4. D1764 J1764 \text{ J}

Correct answer

D. 1764 J1764 \text{ J}

Step-by-step solution

According to the first law of thermodynamics, ΔU=Q+W\Delta U = Q + W.

Since the vessel is thermally insulated, Q=0Q = 0, which gives W=ΔUW = \Delta U.

The change in internal energy of the system is the sum of the changes in internal energy of the water and the copper vessel:

ΔU=mwcwΔT+mcccΔT\Delta U = m_w c_w \Delta T + m_c c_c \Delta T

Substituting the given values:

mw=0.2 kgm_w = 0.2 \text{ kg}, cw=4200 J kg−1 K−1c_w = 4200 \text{ J kg}^{-1} \text{ K}^{-1}

mc=0.1 kgm_c = 0.1 \text{ kg}, cc=420 J kg−1 K−1c_c = 420 \text{ J kg}^{-1} \text{ K}^{-1}

ΔT=17∘C−15∘C=2 K\Delta T = 17^{{}^{{}^{\circ}}}\text{C} - 15^{{}^{{}^{\circ}}}\text{C} = 2 \text{ K}

W=(0.2×4200+0.1×420)×2W = (0.2 \times 4200 + 0.1 \times 420) \times 2

W=(840+42)×2W = (840 + 42) \times 2

W=882×2=1764 JW = 882 \times 2 = 1764 \text{ J}
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