As shown in the figure, a square loop PQRS carrying a current of 6.0 A is situated near a long wire carrying 10 A . Determine the net magnetic force on the square loop.

Step-by-step solution

The magnetic force on a straight wire of length L carrying current I₂ placed at a distance r from a long straight wire carrying current I₁ is given by: F = ₀ I₁ I₂ L 2 r The forces on the horizontal segments PQ and RS are equal and opposite, and their net force is zero. For the side SP of the square loop: The current in SP is downwards, which is anti-parallel to the current in the long wire. Therefore, the force on SP is repulsive (towards the right). Distance r₁ = 1 cm = 0.01 m Length L = 2 cm = 0.02 m F_ SP = 4 1