A solid wire with a radius of 10 cm carries a 5.0 A current that is uniformly distributed across its cross section. Determine the magnetic field B at a point located at a distance of 2 cm from the axis.

Step-by-step solution

Given: Radius of the wire, R = 10 cm = 0.1 m Current, I = 5.0 A Distance from the axis, r = 2 cm = 0.02 m The magnetic field inside a solid cylindrical wire carrying a uniform current at a distance r B d l = ₀ I_ enclosed B(2 r) = ₀ ( I R^2 ) r^2 B = ₀ I r 2 R^2 Substituting the given values: B = 4 10⁻⁷ 5.0 0.02 2 (0.1)^2 B = 2 10⁻⁷ 0.1 0.01 B = 2 10⁻⁶ T = 2.0 T