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Concepts Of Physics MCQ Edition [Volume 2]PhysicsSemiconductors and Semiconductor Devices

A pure semiconductor has 6 10¹⁹ conduction electrons per cubic metre. Determine the number of holes present in a sample measuring 1 cm 1 cm 1 mm .

Options

  1. A6 10¹³
  2. B6 10¹²
  3. C6 10¹⁴
  4. D6 10¹⁰

Correct answer

B. 6 10¹²

Step-by-step solution

In a pure semiconductor, the number density of holes is equal to the number density of conduction electrons. n_ h = n_ e = 6 10¹⁹ m ⁻³ The volume of the sample is given by: V = 1 cm 1 cm 1 mm V = 10⁻² m 10⁻² m 10⁻³ m = 10⁻⁷ m ³ The total number of holes in the sample is: N_ h = n_ h V N_ h = 6 10¹⁹ 10⁻⁷ = 6 10¹²

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