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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Semiconductors and Semiconductor Devices

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Semiconductors and Semiconductor Devices

A pure semiconductor has 6 × 10^ 19 conduction electrons per cubic...

A pure semiconductor has 6×10196 \times 10^{19} conduction electrons per cubic metre. Determine the number of holes present in a sample measuring 1 cm×1 cm×1 mm1 \text{ cm} \times 1 \text{ cm} \times 1 \text{ mm}.

Options

  1. A6×10136 \times 10^{13}
  2. B6×10126 \times 10^{12}
  3. C6×10146 \times 10^{14}
  4. D6×10106 \times 10^{10}

Correct answer

B. 6×10126 \times 10^{12}

Step-by-step solution

In a pure semiconductor, the number density of holes is equal to the number density of conduction electrons.

nh=ne=6×1019 m−3n_{h} = n_{e} = 6 \times 10^{19} \text{ m}^{-3}

The volume of the sample is given by:

V=1 cm×1 cm×1 mmV = 1 \text{ cm} \times 1 \text{ cm} \times 1 \text{ mm}

V=10−2 m×10−2 m×10−3 m=10−7 m3V = 10^{-2} \text{ m} \times 10^{-2} \text{ m} \times 10^{-3} \text{ m} = 10^{-7} \text{ m}^{3}

The total number of holes in the sample is:

Nh=nh×VN_{h} = n_{h} \times V

Nh=6×1019×10−7=6×1012N_{h} = 6 \times 10^{19} \times 10^{-7} = 6 \times 10^{12}
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