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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Specific Heat Capacities of Gases

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Specific Heat Capacities of Gases

The ratio of molar heat capacities for an ideal gas is given as C_p...

The ratio of molar heat capacities for an ideal gas is given as Cp/CV=7/6C_p / C_V = 7/6. Find the change in internal energy of 1.01.0 mole of the gas when its temperature is raised by 50 K50 \text{ K} adiabatically.

Options

  1. A2490 J2490 \text{ J}
  2. B0 J0 \text{ J}
  3. C2905 J2905 \text{ J}
  4. D−2490 J-2490 \text{ J}

Correct answer

A. 2490 J2490 \text{ J}

Step-by-step solution

Given the ratio of molar heat capacities γ=CpCV=76\gamma = \dfrac{C_p}{C_V} = \dfrac{7}{6}

The molar heat capacity at constant volume CVC_V is given by:

CV=Rγ−1=R76−1=6RC_V = \dfrac{R}{\gamma - 1} = \dfrac{R}{\dfrac{7}{6} - 1} = 6R

The change in internal energy for an ideal gas depends only on the change in temperature and is given by:

ΔU=nCVΔT\Delta U = n C_V \Delta T

Substituting the given values n=1.0 moln = 1.0 \text{ mol} and ΔT=50 K\Delta T = 50 \text{ K}:

ΔU=1.0×6R×50=300R\Delta U = 1.0 \times 6R \times 50 = 300R

Using the universal gas constant R=8.3 J mol−1 K−1R = 8.3 \text{ J mol}^{-1} \text{ K}^{-1}:

ΔU=300×8.3=2490 J\Delta U = 300 \times 8.3 = 2490 \text{ J}
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