³² P undergoes beta-decay to ³² S . Calculate the sum of the energy of the antineutrino and the kinetic energy of the -particle. Disregard the recoil of the daughter nucleus. The atomic mass of ³² P is 31.974 u and that of ³² S is 31.972 u .

Step-by-step solution

The beta-decay equation is: ³²₁₅ P ³²₁₆ S + e⁻ + _ e The total energy released ( Q -value) in the ⁻ -decay is shared between the -particle, the antineutrino, and the recoiling daughter nucleus. Disregarding the recoil energy of the daughter nucleus, the sum of the kinetic energy of the -particle and the energy of the antineutrino is equal to the Q -value. The Q -value for ⁻ -decay in terms of atomic masses is: Q = [m(³² P ) - m(³² S )]c^2 Substituting the given atomic masses: m = 31.974 - 31.972 = 0.002 u Convertin