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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
The Nucleus

Concepts Of Physics MCQ Edition [Volume 2] · Physics · The Nucleus

Lithium ( Z = 3 ) possesses two stable isotopes, ^ 6 Li and ^ 7 Li...

Lithium (Z=3Z = 3) possesses two stable isotopes, ^{6}\text{Li}and7Liand ^{7}\text{Li}. When a lithium sample is bombarded with neutrons, electrons and α\alpha-particles are ejected. Identify the correct set of nuclear processes taking place.

Options

  1. A^{6}_{3}\text{Li} + n \to ^{7}_{3}\text{Li}<br>37Li+n→38Li→48Be+e−+νˉ<br> ^{7}_{3}\text{Li} + n \to ^{8}_{3}\text{Li} \to ^{8}_{4}\text{Be} + e^{-} + \bar{\nu}
    ^{8}_{4}\text{Be} \to ^{4}_{2}\text{He} + ^{4}_{2}\text{He}
  2. B^{6}_{3}\text{Li} + n \to ^{7}_{3}\text{Li}<br>37Li+n→38Li→48Be+e−+νˉ<br> ^{7}_{3}\text{Li} + n \to ^{8}_{3}\text{Li} \to ^{8}_{4}\text{Be} + e^{-} + \bar{\nu}
    ^{8}_{4}\text{Be} \to ^{4}_{2}\text{He} + ^{4}_{1}\text{H} + n
  3. C^{6}_{3}\text{Li} + n \to ^{7}_{4}\text{Be} + e^{-} + \bar{\nu}<br>47Be+n→48Be<br> ^{7}_{4}\text{Be} + n \to ^{8}_{4}\text{Be}
    ^{8}_{4}\text{Be} \to ^{4}_{2}\text{He} + ^{4}_{2}\text{He}
  4. D^{6}_{3}\text{Li} + n \to ^{7}_{3}\text{Li}<br>37Li+n→38Li→48Be+e++ν<br> ^{7}_{3}\text{Li} + n \to ^{8}_{3}\text{Li} \to ^{8}_{4}\text{Be} + e^{+} + \nu
    ^{8}_{4}\text{Be} \to ^{4}_{2}\text{He} + ^{4}_{2}\text{He}

Correct answer

A. ^{6}_{3}\text{Li} + n \to ^{7}_{3}\text{Li}<br>37Li+n→38Li→48Be+e−+νˉ<br> ^{7}_{3}\text{Li} + n \to ^{8}_{3}\text{Li} \to ^{8}_{4}\text{Be} + e^{-} + \bar{\nu}
^{8}_{4}\text{Be} \to ^{4}_{2}\text{He} + ^{4}_{2}\text{He}

Step-by-step solution

When a lithium sample containing ^{6}_{3}\text{Li}and37Liand ^{7}_{3}\text{Li} is bombarded with neutrons, the following nuclear reactions occur:

First, ^{6}_{3}\text{Li}capturesaneutrontoformthestableisotope37Licaptures a neutron to form the stable isotope ^{7}_{3}\text{Li}:

^{6}_{3}\text{Li} + n \rightarrow ^{7}_{3}\text{Li}<br><br>Next,37Li<br><br>Next, ^{7}_{3}\text{Li} captures another neutron to form the radioactive isotope ^{8}_{3}\text{Li}:<br><br>37Li+n→38Li:<br><br>^{7}_{3}\text{Li} + n \rightarrow ^{8}_{3}\text{Li}

Since ^{8}_{3}\text{Li}hasanexcessofneutrons,itundergoeshas an excess of neutrons, it undergoes\beta^{-}decaytoform48Bedecay to form ^{8}_{4}\text{Be}, emitting an electron (e−e^{-}) and an antineutrino (νˉ\bar{\nu}):

^{8}_{3}\text{Li} \rightarrow ^{8}_{4}\text{Be} + e^{-} + \bar{\nu}<br><br>Theresulting48Be<br><br>The resulting ^{8}_{4}\text{Be} nucleus is highly unstable and immediately fissions into two α\alpha-particles (^{4}_{2}\text{He}):<br><br>48Be→24He+24He):<br><br>^{8}_{4}\text{Be} \rightarrow ^{4}_{2}\text{He} + ^{4}_{2}\text{He}

This sequence of reactions perfectly explains the ejection of electrons and α\alpha-particles.
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