Concepts Of Physics MCQ Edition [Volume 2]PhysicsThe Nucleus
The decay constant of ¹⁹⁷₈₀ Hg (which decays by electron capture to ¹⁹⁷₇₉ Au ) is 1.8 10⁻⁴ s ⁻¹ . What is the half-life of this isotope?
Options
- A64.2 min
- B128.4 min
- C32.1 min
- D92.6 min
Correct answer
A. 64.2 min
Step-by-step solution
The half-life T_ 1/2 of a radioactive isotope is related to its decay constant by the formula: T_ 1/2 = 2 Given = 1.8 10⁻⁴ s ⁻¹ and using 2 0.693 : T_ 1/2 = 0.693 1.8 10⁻⁴ s T_ 1/2 = 3850 s Converting the half-life from seconds to minutes: T_ 1/2 = 3850 60 min T_ 1/2 64.16 min 64.2 min