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Concepts Of Physics MCQ Edition [Volume 2]

Exam: Concepts Of Physics MCQ Edition [Volume 2]
Subject: Physics
Chapter: The Nucleus

Concepts Of Physics MCQ Edition [Volume 2] · Physics · The Nucleus

Carbon ( Z = 6 ) possessing mass number 11 decays into boron ( Z =...

Carbon (

Z = 6

) possessing mass number

11

decays into boron (

Z = 5

). Identify the type of decay taking place.

Options

A $\beta^{-}$ -decay
B $\alpha$ -decay
C $\beta^{+}$ -decay
D $\gamma$ -decay

Correct answer

C. $\beta^{+}$ -decay

Step-by-step solution

The nuclear reaction for the decay of Carbon-11 into Boron-11 can be written as:

^{11}_{6}\text{C} \rightarrow ^{11}_{5}\text{B} + ^{0}_{+1}e + \nu

<br><br>In this process, the mass number remains unchanged (

A = 11

) while the atomic number decreases by

1

(from

Z = 6

to

Z = 5

). This indicates that a proton is converted into a neutron, emitting a positron (

e^{+}

or

\beta^{+}

) and a neutrino (

\nu

).<br><br>Therefore, the process is

\beta^{+}-decay.

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