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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
The Nucleus

Concepts Of Physics MCQ Edition [Volume 2] · Physics · The Nucleus

^ 197 _ 80 Hg decays to ^ 197 _ 79 Au via electron capture, with a...

^{197}_{80}\text{Hg}decaysto79197Audecays to ^{197}_{79}\text{Au} via electron capture, with a decay constant of 0.2570.257 per day. Determine the other particle or particles that are emitted in this decay.

Options

  1. APositron
  2. BAlpha particle
  3. CAntineutrino
  4. DNeutrino

Correct answer

D. Neutrino

Step-by-step solution

The nuclear reaction for the electron capture process is given by:

^{197}_{80}\text{Hg} + ^{0}_{-1}\text{e} \rightarrow ^{197}_{79}\text{Au} + \nu_{e}<br><br>Inanelectroncaptureprocess,aprotoninthenucleuscapturesaninner−shellelectronandconvertsintoaneutron.Toconservetheleptonnumber,anelectronneutrino(<br><br>In an electron capture process, a proton in the nucleus captures an inner-shell electron and converts into a neutron. To conserve the lepton number, an electron neutrino (\nu_{e}) is emitted.

Thus, the other particle emitted in this decay is a neutrino.
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