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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
The Special Theory of Relativity

Concepts Of Physics MCQ Edition [Volume 2] · Physics · The Special Theory of Relativity

Suspended from a sensitive balance is a 100 W bulb along with its...

Suspended from a sensitive balance is a 100 W100 \text{ W} bulb along with its power supply. Determine the change in the recorded mass after the bulb is kept on for 1 year1 \text{ year}.

Options

  1. A1.05×10−8 kg1.05 \times 10^{-8} \text{ kg}
  2. B9.5×10−8 kg9.5 \times 10^{-8} \text{ kg}
  3. C3.5×10−8 kg3.5 \times 10^{-8} \text{ kg}
  4. D3.5×10−6 kg3.5 \times 10^{-6} \text{ kg}

Correct answer

C. 3.5×10−8 kg3.5 \times 10^{-8} \text{ kg}

Step-by-step solution

The energy radiated by the bulb in one year is given by E=P×tE = P \times t.

Substituting the given values:

P=100 WP = 100 \text{ W}

t=1 year=365×24×60×60 s=3.1536×107 st = 1 \text{ year} = 365 \times 24 \times 60 \times 60 \text{ s} = 3.1536 \times 10^7 \text{ s}

E=100×3.1536×107=3.1536×109 JE = 100 \times 3.1536 \times 10^7 = 3.1536 \times 10^9 \text{ J}

According to the mass-energy equivalence principle, the energy leaving the system as light and heat results in a decrease in the mass of the system.

Δm=Ec2\Delta m = \dfrac{E}{c^2}

Δm=3.1536×109(3×108)2\Delta m = \dfrac{3.1536 \times 10^9}{(3 \times 10^8)^2}

Δm=3.1536×1099×1016\Delta m = \dfrac{3.1536 \times 10^9}{9 \times 10^{16}}

Δm=0.3504×10−7 kg≈3.5×10−8 kg\Delta m = 0.3504 \times 10^{-7} \text{ kg} \approx 3.5 \times 10^{-8} \text{ kg}
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