Concepts Of Physics MCQ Edition [Volume 2]PhysicsThe Special Theory of Relativity
Determine the speed of an electron possessing a kinetic energy of 1 eV .
Options
- A8.37 10⁵ m s ⁻¹
- B5.92 10⁵ m s ⁻¹
- C4.19 10⁵ m s ⁻¹
- D5.92 10⁷ m s ⁻¹
Correct answer
B. 5.92 10⁵ m s ⁻¹
Step-by-step solution
The kinetic energy of the electron is given as K = 1 eV . Converting to Joules: K = 1.6 10⁻¹⁹ J The mass of an electron is m = 9.1 10⁻³¹ kg . Using the formula for kinetic energy K = 1 2 m v^2 , the speed v is: v = 2K m Substituting the values: v = 2 1.6 10⁻¹⁹ 9.1 10⁻³¹ v = 3.2 9.1 10¹² v = 0.3516 10¹² v 0.593 10⁶ m s ⁻¹ = 5.93 10⁵ m s ⁻¹ The closest value among the options is 5.92 10⁵ m s ⁻¹ .