A conducting square loop having side l and resistance R travels in its plane at a uniform velocity v perpendicular to one of its sides. A steady and uniform magnetic field B is present perpendicular to the plane of the loop, as shown in the figure. The induced current in the loop is

Step-by-step solution

The magnetic flux linked with the square loop is given by = BA , where A = l^2 is the area of the loop. Since the magnetic field B is uniform and steady, and the loop is moving completely inside this uniform field, the magnetic flux through the loop remains constant with time. According to Faraday's law of electromagnetic induction, the induced emf is given by: e = - d dt Since is constant, d dt = 0 , which means the induced emf e = 0 . Consequently, the induced current in the loop is: I = e R = 0 Alternatively, us