Concepts Of Physics MCQ Edition [Volume 2]PhysicsMagnetic Field
If projected with identical velocity perpendicular to a magnetic field, which of the following particles will be subjected to a magnetic force of maximum magnitude?
Options
- AProton
- BHe ^+
- CElectron
- DLi ⁺⁺
Correct answer
D. Li ⁺⁺
Step-by-step solution
The magnetic force on a charged particle moving perpendicular to a magnetic field is given by F = qvB . Since the velocity v and magnetic field B are identical for all particles, the magnitude of the magnetic force is directly proportional to the magnitude of the charge q of the particle. The magnitudes of the charges for the given particles are: Proton: e He ^+ : e Electron: e Li ⁺⁺ : 2e Since Li ⁺⁺ has the maximum charge magnitude, it will experience the maximum magnetic force.