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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Magnetic Field due to a Current

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Magnetic Field due to a Current

Examine the scenario illustrated in the figure. The straight wire...

Examine the scenario illustrated in the figure. The straight wire is kept fixed, whereas the loop is free to move under the influence of magnetic force. As a result, the loop will
Examine the scenario illustrated in the figure. The straight wire is kept fixed, whereas the loop is free to move under

Options

  1. Amove away from the wire
  2. Bmove towards the wire
  3. Crotate about the wire
  4. Dremain stationary

Correct answer

B. move towards the wire

Step-by-step solution

The magnetic field due to the straight wire carrying current i1i_1 is directed into the plane of the paper at the location of the loop.

The magnetic forces on the top and bottom horizontal segments of the loop are equal in magnitude and opposite in direction, cancelling each other out.

The left vertical segment carries current in the same direction as the straight wire. Parallel currents attract, so it experiences an attractive force F1F_1 towards the wire.

The right vertical segment carries current in the opposite direction to the straight wire. Antiparallel currents repel, so it experiences a repulsive force F2F_2 away from the wire.

The magnitude of the magnetic field produced by the straight wire decreases with distance (B=μ0i12πrB = \dfrac{\mu_0 i_1}{2\pi r}).

Since the left segment is closer to the straight wire than the right segment, the magnetic field is stronger at the left segment. Therefore, the attractive force F1F_1 is greater than the repulsive force F2F_2.

The net force on the loop is directed towards the straight wire, causing the loop to move towards it.
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