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Concepts Of Physics MCQ Edition [Volume 2]

Exam: Concepts Of Physics MCQ Edition [Volume 2]
Subject: Physics
Chapter: The Special Theory of Relativity

Concepts Of Physics MCQ Edition [Volume 2] · Physics · The Special Theory of Relativity

For a particle travelling at a relativistic speed v , the magnitude...

For a particle travelling at a relativistic speed

v

, the magnitude of its linear momentum is proportional to

Options

A $1 - v^2/c^2$
B $v$
C $\dfrac{v}{\sqrt{1 - v^2/c^2}}$
D $\sqrt{1 - v^2/c^2}$

Correct answer

C. $\dfrac{v}{\sqrt{1 - v^2/c^2}}$

Step-by-step solution

The relativistic linear momentum of a particle of rest mass

m_0

moving with velocity

v

is given by

p = \dfrac{m_0 v}{\sqrt{1 - v^2/c^2}}

Since

m_0

is a constant, the magnitude of linear momentum is proportional to

\dfrac{v}{\sqrt{1 - v^2/c^2}}

.

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