Concepts Of Physics MCQ Edition [Volume 2]PhysicsElectromagnetic Induction
In the circuit depicted in figure (b), the switch is closed at t = 0 and subsequently reopened after a long time at t = t₀ . Which of the following statements is correct regarding the inductor L ?
Options
- AThe voltage across L immediately before t = t₀ is E .
- BThe current in L immediately before t = t₀ is E /R .
- CThe current in L a long time after t = t₀ is E /R .
- DThe current in L immediately after t = 0 is E /R .
Correct answer
B. The current in L immediately before t = t₀ is E /R .
Step-by-step solution
In the given LR circuit, when the switch is closed at t = 0 , the current grows according to the equation: I(t) = E R (1 - e^ -Rt/L ) Immediately after t = 0 , the current is I(0) = 0 . After a long time, the circuit reaches a steady state. The inductor behaves as a short circuit, and the current becomes maximum and constant. The steady-state current immediately before t = t₀ is: I = E R Since the current is constant in steady state, the voltage across the inductor is V_L = L dI dt = 0 . When the switch is reopened