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JEE Main 20254 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
4 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Ionic Equilibrium

JEE Main 2025 · 4 April · Evening Shift · Chemistry · Ionic Equilibrium

x mg of Mg(OH)_2( molar mass =58) is required to be dissolved in...

x mg of Mg(OH)2(\mathrm{Mg}(\mathrm{OH})_2( molar mass =58)=58) is required to be dissolved in 1.0 L of water to produce a pH of 10.0 at 298 K. The value of x is ________ mg. (Nearest integer)
(Given : Mg(OH)2\mathrm{Mg}(\mathrm{OH})_2 is assumed to dissociate completely in H2O\mathrm{H}_2 \mathrm{O})

Correct answer

0

Step-by-step solution

pH=10&pOH=4&[OH−]=10−4\begin{aligned}& \mathrm{pH}=10 \& \mathrm{pOH}=4 \& {\left[\mathrm{OH}^{-}\right]=10^{-4}}\end{aligned}no. of moles of OH−=10−4\mathrm{OH}^{-}=10^{-4}no. of moles of Mg⁡(OH)2=10−42=5×10−5 mass of \operatorname{Mg}(\mathrm{OH})_2=\frac{10^{-4}}{2}=5 \times 10^{-5} \text{ mass of }Mg(OH)2=5×10−5×58×103mg&=2.9\begin{aligned}\mathrm{Mg}(\mathrm{OH})_2 & =5 \times 10^{-5} \times 58 \times 10^3 \mathrm{mg} \& =2.9\end{aligned}$$
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