JEE Main 20252 AprilMorning Shift
- Exam
- JEE Main
- Year
- 2025
- Date
- 2 April
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- Ionic Equilibrium
JEE Main 2025 · 2 April · Morning Shift · Chemistry · Ionic Equilibrium
If equal volumes of (AB_2) and XY (both are salts) aqueous...
If equal volumes of (\mathrm{AB}_2) and XY (both are salts) aqueous solutions are mixed, which of the following combination will give a precipitate of (\mathrm{AY}_2) at 300 K ?
(Given (\mathrm{K}_{\mathrm{sp}}) (at 300 K) for (\mathrm{AY}_2=5.2 \times 10^{-7}))
(Given (\mathrm{K}_{\mathrm{sp}}) (at 300 K) for (\mathrm{AY}_2=5.2 \times 10^{-7}))
Options
- A(3.6 \times 10^{-3} \mathrm{M}~ \mathrm{AB}_2, 5.0 \times 10^{-4} \mathrm{M}~ \mathrm{XY})
- B(2.0 \times 10^{-4} \mathrm{M}~ \mathrm{AB}_2, 0.8 \times 10^{-3} \mathrm{M}~ \mathrm{XY})
- C(2.0 \times 10^{-2} \mathrm{M}~ \mathrm{AB}_2, 2.0 \times 10^{-2} \mathrm{M}~ \mathrm{XY})
- D(1.5 \times 10^{-4} \mathrm{M}~ \mathrm{AB}_2, 1.5 \times 10^{-3} \mathrm{M}~ \mathrm{XY})
Correct answer
C. (2.0 \times 10^{-2} \mathrm{M}~ \mathrm{AB}_2, 2.0 \times 10^{-2} \mathrm{M}~ \mathrm{XY})
Step-by-step solution
When equal volumes are mixed molarity reduce to half.
For precipitation (\mathrm{Q}_{\mathrm{SP}}=\left[\mathrm{A}^{+2}\right]\left[\mathrm{Y}^{-}\right]^2 \gt )
(1) (\mathrm{Q}_{\mathrm{SP}}= \left(1.8 \times10^{-3}\right)\left(\frac{5}{2} \times10^{-4}\right)^2 \lt \mathrm{K}_{\mathrm{sP}})<br />(2) (\mathrm{Q}_{\mathrm{SP}}= \left(10^{-4}\right)\left(0.4 \times10^{-3}\right)^2 \lt \mathrm{K}_{\mathrm{sp}})<br />(3) (\mathrm{Q}_{\mathrm{SP}}= \left(10^{-2}\right)\left(10^{-2}\right)^2 \gt \mathrm{K}_{\mathrm{sP}})
(4) (\mathrm{Q}_{\mathrm{SP}}= \left(\frac{1.5}{2} \times10^{-4}\right)\left(\frac{1.5}{2} \times10^{-3}\right)^2 \lt\mathrm{K}_{\mathrm{sP}}$)
For precipitation (\mathrm{Q}_{\mathrm{SP}}=\left[\mathrm{A}^{+2}\right]\left[\mathrm{Y}^{-}\right]^2 \gt )
(1) (\mathrm{Q}_{\mathrm{SP}}= \left(1.8 \times10^{-3}\right)\left(\frac{5}{2} \times10^{-4}\right)^2 \lt \mathrm{K}_{\mathrm{sP}})<br />(2) (\mathrm{Q}_{\mathrm{SP}}= \left(10^{-4}\right)\left(0.4 \times10^{-3}\right)^2 \lt \mathrm{K}_{\mathrm{sp}})<br />(3) (\mathrm{Q}_{\mathrm{SP}}= \left(10^{-2}\right)\left(10^{-2}\right)^2 \gt \mathrm{K}_{\mathrm{sP}})
(4) (\mathrm{Q}_{\mathrm{SP}}= \left(\frac{1.5}{2} \times10^{-4}\right)\left(\frac{1.5}{2} \times10^{-3}\right)^2 \lt\mathrm{K}_{\mathrm{sP}}$)