The batting average for 27 innings of a cricket player is 47 runs....

Given: The batting average for 27 innings of a cricket player is 47 runs. His highest score exceeds his lowest score by 157 runs. If these two innings are excluded, the average of the remaining 25 innings is 42 runs. Formula used: Average run $=$ Total run in total innings/Total number of innings Calculation: Sum of runs for 27 innings of a cricket player (=47 \times 27=1269) Sum of runs for 25 innings of a cricket player (=42 \times 25=1050) Sum of remaining 2 innings $=1269-1050=219$ Let the minimum score be $x$ and the maximum score be $x+157$ According to the question, ($$\begin{aligned} & x+x+157=219 \\ & \Rightarrow 2 x=219-157 \\ & \Rightarrow 2 x=62 \\ & \Rightarrow x=31 \end{aligned}$$) So, highest score $=157+31$ (\Rightarrow 188) (\therefore) His highest score in an innings is 188.