Ages of father and son add up to 50. Six years back father's age was 6 more than thrice his son's age. What will be the father's age 6 years hence?

Step-by-step solution

Let the age of father be F and that of son be S . ( aligned & F+S=50 (Given) & S=50-F ...(i) aligned ) Six years back father's age was 6 more than thrice his son's age. According to problem: ((F-6)=3(S-6)+6 ) ...(ii) Substituting the value of equation (i) in (ii), we get: ( aligned & F-6=3(50-F-6)+6 & F-6=3(44-F)+6 & F-6=132-3 F+6 & F+3 F=132+6+6 & 4 F=144 & F=144 / 4 & F=36 aligned ) So, father's age 6 years hence (=(36+6)=42 ) Hence, ' 42 ' is the correct answer.