Weight of& A ~is twice that of~ B . Weight of~ B is half that of~ C...

Let the weight of& $D$ be~$4x$

Therefore, weight of $E$~$= \dfrac{D}{2} = \dfrac{4x}{2} = 2x$

Similarly, weight of $C$~$= 3E = 3 \times 2x = 6x$

And, weight of $B$~$= \dfrac{C}{2} = \dfrac{6x}{2} = 3x$

Therefore, weight of $A$~$= 2B = 2 \times 3x = 6x$

Thus, both $A$~and~$C$ are the heaviest.