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JEE Main202522 Jan 2025Evening ShiftChemistryIonic EquilibriumActual

The molar solubility(s) of zirconium phosphate with molecular formula ( Zr ⁴⁺ )₃ ( PO ₄³⁻ )₄ is given by relation :

Options

  1. A( K _ sp 9612 )^ 1 3
  2. B( K _ sp 6912 )^ 1 7
  3. C( K _ sp 8435 )^ 1 7
  4. D( K _ sp 5348 )^ 1 6

Correct answer

B. ( K _ sp 6912 )^ 1 7

Step-by-step solution

array cc Zr ₃ ( PO ₄ )₄( ~s ) & 3 Zr ⁺⁴( aq )+4 PO ₄⁻³( aq ) - & 3 ~s 4 ~s array aligned & K _ sp =(3 ~s )^3(4 ~s )^4=6912 ~s ^7 & ~s = ( K _ sp 6912 )^ 1 / 7 aligned

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