If the solubility product of PbS is 8 × 10 ^ - 28 , then the...

$PbS\left(s\right)\overset{}{⇌}{Pb}^{2 +}\left(aq\right) + {S}^{2 -}\left(aq\right)$

Let us consider the solubility of $PbS$ is "$S$" $M$.

Thus,

Solubility product $= \left[{Pb}^{2 +}\left(aq\right)\right]\left[{S}^{2 -}\left(aq\right)\right]$

Ksp = \left[{Pb}^{2 +}\left(aq\right)\right]\left[{S}^{2 -}\left(aq\right)\right] ⋯ \left(i\right)$</p><p>We know</p><p>${K}_{sp} = {S}^{2}$</p><p>$S = \sqrt{{K}_{sp}} = \sqrt{8 \times {10}^{- 28}} = 2\sqrt{2} \times {10}^{- 14}$</p><p>$= 2 . 82 \times {10}^{- 14}$</p><p>$= 282 \times {10}^{- 16}