At 310K , the solubility of CaF _ 2 in water is 2 . 34 × 10 ^ - 3 g...

The solubility product constant is the equilibrium constant for the dissolution of a solid substance into an aqueous solution. It is denoted by the symbol ${K}_{sp}$.

Solubility of ${CaF}_{2} = Smole / / L$

$S = \dfrac{2 . 34 \times {10}^{- 3}}{0 . 1 \times 78} = \dfrac{2 . 34}{78} \times {10}^{- 2} = 3 \times {10}^{- 4}mol / L$

${K}_{sp}\left({CaF}_{2}\right) = 4{S}^{3} = 4{\left(3 \times {10}^{- 4}\right)}^{3}$

$= 108 \times {10}^{- 12}$

$= 0 . 0108 \times {10}^{- 8}{\left(mol / L\right)}^{3}$