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JEE Main 20211 SeptemberEvening Shift
Exam
JEE Main
Year
2021
Date
1 September
Shift
Evening Shift
Subject
Chemistry
Chapter
Ionic Equilibrium

JEE Main 2021 · 1 September · Evening Shift · Chemistry · Ionic Equilibrium

The molar solubility of Zn ( OH ) _ 2 in 0 . 1MNaOH solution is x ×...

The molar solubility of Zn(OH)2in0.1MNaOHZn ( OH{)}_{2} in 0 . 1MNaOH solution is x×10−18M.x \times {10}^{- 18}M . The value of xx is _____ . (Nearest integer)

\left(\text{Given :TheThesolubility product of}Zn ( OH{)}_{2}\text{is}2 \times {10}^{- 20}\right)$

Correct answer

0

Step-by-step solution

Zn(OH)2(s)⇌Zn+2(aq)+2OH−(aq)S(0.1+2s)≈0.1Zn ( OH{)}_{2} ( s ) ⇌ {Zn}^{+ 2} ( aq ) + 2{OH}^{-} ( aq ) S ( 0 . 1 + 2s ) \approx 0 . 1

Ksp=S(0.1)2{K}_{sp} = S ( 0 . 1{)}^{2}

2×10−20=s×10−2⇒s=2×10−182 \times {10}^{- 20} = s \times {10}^{- 2} ⇒ s = 2 \times {10}^{- 18}

=x×10−18= x \times {10}^{- 18}

x=2x = 2

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