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JEE Main202131 Aug 2021Morning ShiftChemistryIonic EquilibriumActual

A 3 B 2 is a sparingly soluble salt of molar mass M g   mol - 1 and solubility x   g   L - 1 . The solubility product satisfies K sp = a x M 5 . The value of a is __________ . (Integer answer)

Correct answer

0

Step-by-step solution

Solubility = x m mole/lit A 3 B 2 s ⇌ 3 A 2 + 3 x M ( aqs ) + 2 B 3 - ( aqs ) 2 x M K sp = 3 x M 3 2 x M 2 = 3 3 2 2 x m 5 = 27 × 4 x m 5 = 108 x m 5 = a x M 5 So a = 108

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