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The solubility of CdSO 4 in water is 8 . 0 × 10 - 4 mol L - 1 . Its solubility in 0 . 01 M H 2 SO 4 solution is ___ × 10 - 6 mol L - 1 (Round off to the Nearest integer) (Assume that solubility is much less than 0 . 01 M )

Correct answer

0

Step-by-step solution

In pure water, K sp = S 2 = 8 × 10 - 4 2 = 64 × 10 - 8 In 0 . 01   M   H 2 SO 4 H 2 SO 4 ( aq ) x → 2 H ( aq ) + x + SO 4 2 - ( aq . ) ( x + 0 . 01 ) K sp = x ( x + 0 . 01 ) = 64 × 10 - 8 x + 0 . 01 ≅ 0 . 01   M So, x ( 0 . 01 ) = 64 × 10 - 8 x = 64 × 10 - 6 M

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