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Sulphurous acid H 2 SO 3 has Ka 1 = 1 . 7 × 10 - 2 and Ka 2 = 6 . 4 × 10 - 8 . The pH of 0 . 588 M H 2 SO 3 is____________ ( Round off to the Nearest Integer ) .

Correct answer

0

Step-by-step solution

H 2 SO 3 [ Dibasic acid ] c = 0 . 588   M ⇒ pH of solution is due to First dissociation only since K a 1 > > Ka 2 ⇒ First dissociation of H 2 SO 3 H 2 SO 3 ( aq ) ⇌ H ⊕ ( aq ) + HSO 3 - ( aq )   :   ka 1 = 1 . 7 × 10 - 2 t =             0 t               C - x                             x            

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