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JEE Main202125 Feb 2021Evening ShiftChemistryIonic EquilibriumActual

The solubility of Ca OH 2 in water is : [Given : The solubility product of Ca OH 2 in water = 5 . 5 × 10 - 6 ]

Options

  1. A1 . 77 × 10 - 2
  2. B1 . 77 × 10 - 6
  3. C1 . 11 × 10 - 2
  4. D1 . 11 × 10 - 6

Correct answer

C. 1 . 11 × 10 - 2

Step-by-step solution

Given that, The solubility product of Ca OH 2 in water = 5 . 5 × 10 - 6 Ca OH 2 ⇌ Ca 2 + aq s + 2 OH - aq 2 s k sp = s 2   s 2 ⇒ 5 . 5 × 10 - 6 = 4   s 3 4 s 3 = 5 . 5 × 10 - 6 s = 5 . 5 4 1 / 3 × 10 - 2 s = 1 . 11 × 10 - 2

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